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No. | Question | Time Taken (sec) | Average Time (sec) | Best Time (sec) |
---|---|---|---|---|
1 |
A new student- Diksha joins and failed in Sociology by 5 marks. Had she scored 10 more marks in Sociology, her total marks in both the subjects would have been 145. Find her marks in Botany. |
221 | 336.33 | 4.76 |
2 |
The ratio of the marks of Cathy in Sociology and Botany is 3 : 4. Find the marks of Ray in Botany. |
119 | 70.5 | 1.28 |
3 |
The marks of Ray in Botany are 25 more than double the marks of Ray in Sociology. Find the marks of Cathy in Botany. |
1 | 39.72 | 1.21 |
4 |
What are the passing marks of Botany? |
NA | 25.87 | 0.16 |
5 |
What is the average marks of all five students in Sociology? |
6 | 38.38 | 3.63 |
6 |
If it is advised that chemical exfoliants and ceramides should be minimum 30% and 20% respectively. In how many different ways can we prepare this formula mixing exactly two ingredients in same quantity? |
129 | 110.12 | 1.68 |
7 |
Which of the following mixtures of two ingredients will result in the lowest cost incurred such that there is atleast 30% of retinol and 10% of Salicyclic acid. |
72 | 101.69 | 1.1 |
8 |
In what proportion B, D and E should be mixed so that there is atleast 30% ceramides and the cost incurred is the lowest? |
13 | 62.13 | 0.88 |
9 |
For dry skin face, company is planning to have a face wash which has at least 40% of retinol, no more than 20% of ceramides and at least 5% of salicylic acid. Which of the following combinations of equally mixed ingredients satisfies this? |
NA | 48.79 | 1.22 |
10 |
If D and E are mixed in such proportion that the amount of salicylic acid is exactly 3% of the mixture, then the percentage of ceramides in this mixture is? |
NA | 50.74 | 0.48 |
11 |
What percent of commerce students are males? |
NA | 172.2 | 1.22 |
12 |
If 25% of students in maths science who love sports are male, then the difference between the number of female students who love sports and male students who do not love sports in that section is? |
NA | 48.97 | 1.45 |
13 |
What can be the least number of female students who love sports? |
NA | 10.9 | 1.45 |
14 |
If 75% of the students who love sports are females, then what percent of male students who do not love sports is the female students who do not love sports? |
NA | 23.66 | 0.77 |
15 |
What percent of female students are not in maths science section? |
NA | 28.83 | 0.29 |
Question no.1
The following table shows the marks of Abhi, Cathy, Aman, Dolly and Ray in Sociology and Botany.
| Sociology
| Botany
|
Abhi
|
|
|
Cathy
| 75
|
|
Aman
|
|
|
Dolly
|
| 110
|
Ray
|
|
|
1. The passing marks in Sociology and Botany is 60% and above and 50% and above respectively.
2. The total marks of Cathy and Ray in the two subjects is same.
3. Both Abhi and Aman scored 10 more marks in Botany than in Sociology.
4. Dolly and Aman scored 70% and 80% of the total marks in sociology respectively.
5. The marks of Abhi in Botany are 20 more than the marks of Ray in Sociology.
6. Ray failed in Sociology and Abhi failed in Botany by 10 marks and 5 marks respectively.
7. The marks of Aman in Sociology are 40% of the total marks of Dolly and Aman in Botany.
A new student- Diksha joins and failed in Sociology by 5 marks. Had she scored 10 more marks in Sociology, her total marks in both the subjects would have been 145. Find her marks in Botany.
60
70
80
90
Explanation
Answer- C
| Sociology
| Botany
|
Abhi
| 0.6 a + 10
| 0.5 b - 5
|
Cathy
| 75
|
|
Aman
| 0.4 (p + 110) = 0.8 a
| P
|
Dolly
| 0.7 a
| 110
|
Ray
| 0.6 a – 10
|
|
Let the total marks of Sociology and Botany be a and b respectively.
Passing marks in Sociology and Botany is 0.6 a and 0.5 b respectively.
Aman scored 10 more marks in Botany than in Sociology.
P = 10 + 0.4(p + 110)
P – 10 = 0.4p + 44
0.6p = 54
P = 90
0.8a = 80
A = 100
Aman scored 10 more marks in Botany than in Sociology.
0.5b – 5 = 10 + 60 = 70
b = 150
| Sociology
| Botany
|
Abhi
| 60
| 70
|
Cathy
| 75
| m
|
Aman
| 80
| 90
|
Dolly
| 70
| 110
|
Ray
| 50
| n
|
The total marks of Cathy and Ray in the two subjects is same.
75 + m = 50 + n
25 + m = n
Diksha failed by 5 marks.
She scored 60- 5 = 55 marks in sociology
Total marks = 145
Marks in Botany = 145 – (55 + 10) = 80
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 14.00% users answered right
Subject: Tables
Result: Incorrect
Question no.2
The following table shows the marks of Abhi, Cathy, Aman, Dolly and Ray in Sociology and Botany.
| Sociology
| Botany
|
Abhi
|
|
|
Cathy
| 75
|
|
Aman
|
|
|
Dolly
|
| 110
|
Ray
|
|
|
1. The passing marks in Sociology and Botany is 60% and above and 50% and above respectively.
2. The total marks of Cathy and Ray in the two subjects is same.
3. Both Abhi and Aman scored 10 more marks in Botany than in Sociology.
4. Dolly and Aman scored 70% and 80% of the total marks in sociology respectively.
5. The marks of Abhi in Botany are 20 more than the marks of Ray in Sociology.
6. Ray failed in Sociology and Abhi failed in Botany by 10 marks and 5 marks respectively.
7. The marks of Aman in Sociology are 40% of the total marks of Dolly and Aman in Botany.
The ratio of the marks of Cathy in Sociology and Botany is 3 : 4. Find the marks of Ray in Botany.
125
110
135
120
Explanation
Answer- A
| Sociology
| Botany
|
Abhi
| 0.6 a + 10
| 0.5 b - 5
|
Cathy
| 75
|
|
Aman
| 0.4 (p + 110) = 0.8 a
| P
|
Dolly
| 0.7 a
| 110
|
Ray
| 0.6 a – 10
|
|
Let the total marks of Sociology and Botany be a and b respectively.
Passing marks in Sociology and Botany is 0.6 a and 0.5 b respectively.
Aman scored 10 more marks in Botany than in Sociology.
P = 10 + 0.4(p + 110)
P – 10 = 0.4p + 44
0.6p = 54
P = 90
0.8a = 80
A = 100
Aman scored 10 more marks in Botany than in Sociology.
0.5b – 5 = 10 + 60 = 70
b = 150
| Sociology
| Botany
|
Abhi
| 60
| 70
|
Cathy
| 75
| m
|
Aman
| 80
| 90
|
Dolly
| 70
| 110
|
Ray
| 50
| n
|
The total marks of Cathy and Ray in the two subjects is same.
75 + m = 50 + n
25 + m = n
75 : m = 3 : 4
m = 100
n = 25 + 100 = 125
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 16.00% users answered right
Subject: Tables
Result: Unanswered
Question no.3
The following table shows the marks of Abhi, Cathy, Aman, Dolly and Ray in Sociology and Botany.
| Sociology
| Botany
|
Abhi
|
|
|
Cathy
| 75
|
|
Aman
|
|
|
Dolly
|
| 110
|
Ray
|
|
|
1. The passing marks in Sociology and Botany is 60% and above and 50% and above respectively.
2. The total marks of Cathy and Ray in the two subjects is same.
3. Both Abhi and Aman scored 10 more marks in Botany than in Sociology.
4. Dolly and Aman scored 70% and 80% of the total marks in sociology respectively.
5. The marks of Abhi in Botany are 20 more than the marks of Ray in Sociology.
6. Ray failed in Sociology and Abhi failed in Botany by 10 marks and 5 marks respectively.
7. The marks of Aman in Sociology are 40% of the total marks of Dolly and Aman in Botany.
The marks of Ray in Botany are 25 more than double the marks of Ray in Sociology. Find the marks of Cathy in Botany.
100
110
90
105
Explanation
Answer- A
| Sociology
| Botany
|
Abhi
| 0.6 a + 10
| 0.5 b - 5
|
Cathy
| 75
|
|
Aman
| 0.4 (p + 110) = 0.8 a
| P
|
Dolly
| 0.7 a
| 110
|
Ray
| 0.6 a – 10
|
|
Let the total marks of Sociology and Botany be a and b respectively.
Passing marks in Sociology and Botany is 0.6 a and 0.5 b respectively.
Aman scored 10 more marks in Botany than in Sociology.
P = 10 + 0.4(p + 110)
P – 10 = 0.4p + 44
0.6p = 54
P = 90
0.8a = 80
A = 100
Aman scored 10 more marks in Botany than in Sociology.
0.5b – 5 = 10 + 60 = 70
b = 150
| Sociology
| Botany
|
Abhi
| 60
| 70
|
Cathy
| 75
| m
|
Aman
| 80
| 90
|
Dolly
| 70
| 110
|
Ray
| 50
| n
|
The total marks of Cathy and Ray in the two subjects is same.
75 + m = 50 + n
25 + m = n
Marks of Ray in Botany = 2(50) + 25 = 125
Marks of Cathy in Botany = 125 – 25 = 100
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 21.00% users answered right
Subject: Tables
Result: Unanswered
Question no.4
The following table shows the marks of Abhi, Cathy, Aman, Dolly and Ray in Sociology and Botany.
| Sociology
| Botany
|
Abhi
|
|
|
Cathy
| 75
|
|
Aman
|
|
|
Dolly
|
| 110
|
Ray
|
|
|
1. The passing marks in Sociology and Botany is 60% and above and 50% and above respectively.
2. The total marks of Cathy and Ray in the two subjects is same.
3. Both Abhi and Aman scored 10 more marks in Botany than in Sociology.
4. Dolly and Aman scored 70% and 80% of the total marks in sociology respectively.
5. The marks of Abhi in Botany are 20 more than the marks of Ray in Sociology.
6. Ray failed in Sociology and Abhi failed in Botany by 10 marks and 5 marks respectively.
7. The marks of Aman in Sociology are 40% of the total marks of Dolly and Aman in Botany.
What are the passing marks of Botany?
70
80
85
75
Explanation
Answer- D
| Sociology
| Botany
|
Abhi
| 0.6 a + 10
| 0.5 b - 5
|
Cathy
| 75
|
|
Aman
| 0.4 (p + 110) = 0.8 a
| P
|
Dolly
| 0.7 a
| 110
|
Ray
| 0.6 a – 10
|
|
Let the total marks of Sociology and Botany be a and b respectively.
Passing marks in Sociology and Botany is 0.6 a and 0.5 b respectively.
Aman scored 10 more marks in Botany than in Sociology.
P = 10 + 0.4(p + 110)
P – 10 = 0.4p + 44
0.6p = 54
P = 90
0.8a = 80
A = 100
Aman scored 10 more marks in Botany than in Sociology.
0.5b – 5 = 10 + 60 = 70
b = 150
| Sociology
| Botany
|
Abhi
| 60
| 70
|
Cathy
| 75
| m
|
Aman
| 80
| 90
|
Dolly
| 70
| 110
|
Ray
| 50
| n
|
The total marks of Cathy and Ray in the two subjects is same.
75 + m = 50 + n
25 + m = n
Maximum marks of Botany = 150
Passing marks = 50% of 150 = 75
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 14.00% users answered right
Subject: Tables
Result: Unanswered
Question no.5
The following table shows the marks of Abhi, Cathy, Aman, Dolly and Ray in Sociology and Botany.
| Sociology
| Botany
|
Abhi
|
|
|
Cathy
| 75
|
|
Aman
|
|
|
Dolly
|
| 110
|
Ray
|
|
|
1. The passing marks in Sociology and Botany is 60% and above and 50% and above respectively.
2. The total marks of Cathy and Ray in the two subjects is same.
3. Both Abhi and Aman scored 10 more marks in Botany than in Sociology.
4. Dolly and Aman scored 70% and 80% of the total marks in sociology respectively.
5. The marks of Abhi in Botany are 20 more than the marks of Ray in Sociology.
6. Ray failed in Sociology and Abhi failed in Botany by 10 marks and 5 marks respectively.
7. The marks of Aman in Sociology are 40% of the total marks of Dolly and Aman in Botany.
What is the average marks of all five students in Sociology?
Explanation
Answer- 67
| Sociology
| Botany
|
Abhi
| 0.6 a + 10
| 0.5 b - 5
|
Cathy
| 75
|
|
Aman
| 0.4 (p + 110) = 0.8 a
| P
|
Dolly
| 0.7 a
| 110
|
Ray
| 0.6 a – 10
|
|
Let the total marks of Sociology and Botany be a and b respectively.
Passing marks in Sociology and Botany is 0.6 a and 0.5 b respectively.
Aman scored 10 more marks in Botany than in Sociology.
P = 10 + 0.4(p + 110)
P – 10 = 0.4p + 44
0.6p = 54
P = 90
0.8a = 80
A = 100
Aman scored 10 more marks in Botany than in Sociology.
0.5b – 5 = 10 + 60 = 70
B = 150
| Sociology
| Botany
|
Abhi
| 60
| 70
|
Cathy
| 75
| m
|
Aman
| 80
| 90
|
Dolly
| 70
| 110
|
Ray
| 50
| n
|
The total marks of Cathy and Ray in the two subjects is same.
75 + m = 50 + n
25 + m = n
Average marks of all five students in Sociology = (60 +75 + 80 +70 +50)/5 = 67
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 5.00% users answered right
Subject: Tables
Result: Unanswered
Question no.6
Hindustan Unilever’s R&D is trying to make various formulations for making a new face wash. It is considering 5 ingredients, A, B, C, D and E which can be used in different proportions in the formulations. The cost per unit of the ingredients A, B, C, D and E are 250, 150, 120, 180, 40 respectively.
The table below is the composition of these ingredients.
If it is advised that chemical exfoliants and ceramides should be minimum 30% and 20% respectively. In how many different ways can we prepare this formula mixing exactly two ingredients in same quantity?
0
1
2
More than 2
Explanation
Answer-BFor chemical exfoliant to be minimum 30%, there are only 3 ways of mixing 2 ingredients. They are (A, B) , (A, D) and (A,E)
The percent of ceramides in (A, B) , (A,D) and (A,E) is 20%, 17.5% and 12.5% respectively.
Therefore there is only one way of mixing two ingredients such that chemical exfoliants and ceramides should be minimum 30% and 20% respectively. (A, B).
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 13.00% users answered right
Subject: Tables
Result: Incorrect
Question no.7
Hindustan Unilever’s R&D is trying to make various formulations for making a new face wash. It is considering 5 ingredients, A, B, C, D and E which can be used in different proportions in the formulations. The cost per unit of the ingredients A, B, C, D and E are 250, 150, 120, 180, 40 respectively.
The table below is the composition of these ingredients.
Which of the following mixtures of two ingredients will result in the lowest cost incurred such that there is atleast 30% of retinol and 10% of Salicyclic acid.
D and E
C and D
B and C
A and E
Explanation
Answer- A
D and E when mixed in the proportion 1:2, gives 10% salicylic acid and 45% retinol.
Cost incurred = 180 +40*2 = 260
Option (b) C and D
Mixing in the ratio of 1:1, both the condition satisfies.
Cost incurred= 180+120 = 300.
Option (c): B and C
Will not fulfil the required condition for any ratio.
Option (d): A and E
Mixing in the ratio of 1:1, both the condition satisfies.
Cost incurred= 250+40 = 290.
Therefore option (a) is the answer.
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 12.00% users answered right
Subject: Tables
Result: Incorrect
Question no.8
Hindustan Unilever’s R&D is trying to make various formulations for making a new face wash. It is considering 5 ingredients, A, B, C, D and E which can be used in different proportions in the formulations. The cost per unit of the ingredients A, B, C, D and E are 250, 150, 120, 180, 40 respectively.
The table below is the composition of these ingredients.
In what proportion B, D and E should be mixed so that there is atleast 30% ceramides and the cost incurred is the lowest?
2:2:4
3:3:4
2:1:1
2:3:1
Explanation
Answer-CB, D and E contain 35%, 30%and 20% of ceramides.
Solution
Option (a) and option (b) contains less than 30% ceramide.
Option (c): (2*35%) +(1*30%)+(1*20%) = 120/4 = 30%
Cost incurred = (4*150) + (2*180)+(2*40) = 600+360+80 = 1040
Option (d) : (2*35%)+(3*30%)+(1*20%) = 70+90+20 = 180/6 = 30%
Cost incurred = (2*150) +(5*180)+(1*20) = 1220.
Therefore the answer is c
Marks: 0.00
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 18.00% users answered right
Subject: Tables
Result: Unanswered
Question no.9
Hindustan Unilever’s R&D is trying to make various formulations for making a new face wash. It is considering 5 ingredients, A, B, C, D and E which can be used in different proportions in the formulations. The cost per unit of the ingredients A, B, C, D and E are 250, 150, 120, 180, 40 respectively.
The table below is the composition of these ingredients.
For dry skin face, company is planning to have a face wash which has at least 40% of retinol, no more than 20% of ceramides and at least 5% of salicylic acid. Which of the following combinations of equally mixed ingredients satisfies this?
A and D
A and E
A and B
D and E
Explanation
Answer- BOnly Option b satisfies these.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 26.00% users answered right
Subject: Tables
Result: Unanswered
Question no.10
Hindustan Unilever’s R&D is trying to make various formulations for making a new face wash. It is considering 5 ingredients, A, B, C, D and E which can be used in different proportions in the formulations. The cost per unit of the ingredients A, B, C, D and E are 250, 150, 120, 180, 40 respectively.
The table below is the composition of these ingredients.
If D and E are mixed in such proportion that the amount of salicylic acid is exactly 3% of the mixture, then the percentage of ceramides in this mixture is?
32%
30%
25%
28%
Explanation
Answer-DThe percent of salicyclic acid is 15% in E and 0% in D. S this 15% should be equal to 3%. 15 is 3% of 500. D and E must be mixed in the ratio of 4:1 for salicyclic acid to be exactly 3%.
Therefore the percentage of ceramide in this mixture = 4*30+1*20 = 140= 140/5 = 28%.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 8.00% users answered right
Subject: Tables
Result: Unanswered
Question no.11
In a school there are 1600 students of which 60% are in maths science section, 20% are in arts section and 20% are in commerce students. Below is the proportion of male students and the students who love sports. The number of male commerce students is 7 times the number of male students in arts section and the number of maths science students who loved sports is 3 times the number of students in arts section who love sports.
SECTION | MALE | SPORTS LOVER |
ARTS | ||
COMMERCE | 0.07 | |
MATHS-SCIENCE | 0.27 | |
TOTAL | 0.475 | 0.58 |
What percent of commerce students are males?
80%
90%
75%
85%
Explanation
Answer- B
Let x number of students are male students in arts section.
Then the number of male students in commerce section = 7x.
Let y be the number of students in arts section who love sports.
Then the number of students in maths science section who love sports = 3y
Total male students in all sections = 1600*.475 = 760
Total students in maths science = 1600*.6 = 960
Total male students in maths-science students = 1600*.27=432
X+7x+432 = 760
8x= 328
X= 41 and 7x = 287
And total number of students who love sports = 1600*.58=928
Number of students in commerce section = 1600*.2= 320
Total number of students from commerce section who love sports = 1600*.07= 112
Therefore, y +112+3y = 928
4y+112= 928
y= 816/4= 204
and 3y = 612.
So, our table become like this.
SECTION | MALE | SPORTS LOVER |
ARTS | 41 | 204 |
COMMERCE | 287 | 112 |
MATHS-SCIENCE | 432 | 612 |
TOTAL | 760 | 928 |
Percent of Commerce students that are males = 287/320 * 100\(≈\)90%.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 10.00% users answered right
Subject: Tables
Result: Unanswered
Question no.12
In a school there are 1600 students of which 60% are in maths science section, 20% are in arts section and 20% are in commerce students. Below is the proportion of male students and the students who love sports. The number of male commerce students is 7 times the number of male students in arts section and the number of maths science students who loved sports is 3 times the number of students in arts section who love sports.
SECTION | MALE | SPORTS LOVER |
ARTS | ||
COMMERCE | 0.07 | |
MATHS-SCIENCE | 0.27 | |
TOTAL | 0.475 | 0.58 |
If 25% of students in maths science who love sports are male, then the difference between the number of female students who love sports and male students who do not love sports in that section is?
150
306
Cannot be determined
180
Explanation
Answer- DTotal number of students in maths science who love sports = 612
Out of which male are = 612*.25 = 153
Male who do not love sports in maths science section = 432-153= 279
Females who love sports from maths science section = 612-153 = 459
Therefore the difference = 459-279= 180.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 4.00% users answered right
Subject: Tables
Result: Unanswered
Question no.13
In a school there are 1600 students of which 60% are in maths science section, 20% are in arts section and 20% are in commerce students. Below is the proportion of male students and the students who love sports. The number of male commerce students is 7 times the number of male students in arts section and the number of maths science students who loved sports is 3 times the number of students in arts section who love sports.
SECTION | MALE | SPORTS LOVER |
ARTS | ||
COMMERCE | 0.07 | |
MATHS-SCIENCE | 0.27 | |
TOTAL | 0.475 | 0.58 |
What can be the least number of female students who love sports?
168
343
180
163
Explanation
Answer- BIn order to minimize the female sports lover students we need to maximize the male sports lover students.
In arts section, the maximum number of male students who can love sports is 41.
So the minimum number of female students who love sports from arts section = 204-41= 163
From commerce section, the minimum number of female sports lover can be zero.
From maths-science section, minimum number of female students who love sports = 612-432=180.
Therefore the least number of female sports lover = 163+180=343.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 8.00% users answered right
Subject: Tables
Result: Unanswered
Question no.14
In a school there are 1600 students of which 60% are in maths science section, 20% are in arts section and 20% are in commerce students. Below is the proportion of male students and the students who love sports. The number of male commerce students is 7 times the number of male students in arts section and the number of maths science students who loved sports is 3 times the number of students in arts section who love sports.
SECTION | MALE | SPORTS LOVER |
ARTS | ||
COMMERCE | 0.07 | |
MATHS-SCIENCE | 0.27 | |
TOTAL | 0.475 | 0.58 |
If 75% of the students who love sports are females, then what percent of male students who do not love sports is the female students who do not love sports?
24%
25%
27%
32%
Explanation
Answer- CTotal number of sport lover students = 928
Out of which female students are = 928*.75 = 696
And male students = 928-696= 232
Total female students in the school = 1600-760 = 840
Female who do not love sports = 840-696 = 144
And male students who do not love sports = 760-232= 528
Therefore, 144/528 * 100
144/528 lies between 1/3 and ¼. So the percentage is greater than 25% and lesser than 33.33%.
Option (a) and (b) are eliminated.
By observing we can say that 144/528 is close to ¼ but away from 1/3. Therefore option (d) is also eliminated.
Option (c) is the answer.
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 12.00% users answered right
Subject: Tables
Result: Unanswered
Question no.15
In a school there are 1600 students of which 60% are in maths science section, 20% are in arts section and 20% are in commerce students. Below is the proportion of male students and the students who love sports. The number of male commerce students is 7 times the number of male students in arts section and the number of maths science students who loved sports is 3 times the number of students in arts section who love sports.
SECTION | MALE | SPORTS LOVER |
ARTS | ||
COMMERCE | 0.07 | |
MATHS-SCIENCE | 0.27 | |
TOTAL | 0.475 | 0.58 |
What percent of female students are not in maths science section?
32%
37%
41%
43%
Explanation
Answer- BTotal female students = 1600-760= 840
Total female students in arts section = 320-41 = 279
Total female students on commerce section = 320-287 = 33
Therefore, Total number of female students that are not in maths science section = 279+33= 312
So, we need to find 312/840*100.
40% of 840 = 336
Therefore it is less than 40%.
Option (c) and (d) are eliminated
Option is very close to 30% of 840. But 30% of 840 = 252, which is very far from 312. Therefore the answer is 37%
Marks:
Negative Marks: 0.00
Difficulty Level: Easy
Trivia: 11.00% users answered right
Subject: Tables
Result: Unanswered
Section | Marks | Total Qs | Attempts | Correct Qs | Incorrect Qs | Accuracy % | Percentage | Percentile | Topper's Score | Total Time | Time Taken |
---|---|---|---|---|---|---|---|---|---|---|---|
OVERALL | 0.00 | 15 | 3 | 0 | 3 | 0 | 0 | 28.25 | NA | 0:15:00 | 0:09:23 |
Tables | 0.00 | 15 | 3 | 0 | 3 | 0 | 0.00 | 27.31 | 15.00 |
Subject Name | Total Questions | Correct | Incorrect | Unanswered | Score |
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Overall Analysis
Let's look at your wins!
No. of correct questions | ||
Area | Total Qs = T | Correct Qs = C |
---|---|---|
Tables | 15 | 0 |
Overall | 15 | 0 |
It's all about percentage not percentile!
No. of correct questions | ||
Marks scored in correct | Total Marks | % of marks scored |
---|---|---|
0 | 0.00 | 0% |
0 | 0.00 | 0% |
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Sectional Analysis
Score : 0.00